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x+5y = 57 x = 57-5y -3(x) + 4y = 95 so whats x and y?
from your second equation, we can write: \[x=57-5y\] now I substitute that expression for y, into your first equation, and I get: \[-3(57-5y)+4y=95\] which can be easily solved for y
If we solve that equation, we get: \[-171+15y+4y=95\] \[19 y=266\] and then: \[y=\frac{ 266 }{ 19 }=4\]
now I substitute y=4 in the above expression for x, namely: x=57-5y\[x=57-5*14==57-70=-13\] so x=-13 and y=14 please, is my reasoning clear for you?
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