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Mathematics 18 Online
OpenStudy (anonymous):

Please help http://gyazo.com/3f8b2622e04c35555f2af2f5f4874a11

OpenStudy (jhannybean):

The formula for direct variatioin is : \(y=kx\)

OpenStudy (jhannybean):

We're given values of \(y\) and or \(x\). we could use these to figure out our value of \(k\)

OpenStudy (jhannybean):

Solving for \(k\) we get, \(k=\dfrac{y}{x}\)

OpenStudy (anonymous):

What would that be in numbers?

OpenStudy (jhannybean):

well, let's take our first two values, \(x=2~,~ y=5\)

OpenStudy (jhannybean):

If you plugged those in for \(k=\dfrac{y}{x}\) what would you attain as you \(k\) value?

OpenStudy (anonymous):

can u tell me the answer plz!111

OpenStudy (anonymous):

Would it be 2.5?

OpenStudy (jhannybean):

How did you get 2.5? :P

OpenStudy (anonymous):

i have no idea xD

OpenStudy (anonymous):

Objection there is no 1.7x^2 as a answer

OpenStudy (anonymous):

Jhannybean

OpenStudy (anonymous):

@Jhannybean

OpenStudy (jhannybean):

Once you figure out your k value, all you have to do is rewrite your equation in the format \(y=kx\) with your new found k value.

OpenStudy (jhannybean):

so what does \(k=\dfrac{5}{2} =~?\)

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