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The formula for direct variatioin is : \(y=kx\)
We're given values of \(y\) and or \(x\). we could use these to figure out our value of \(k\)
Solving for \(k\) we get, \(k=\dfrac{y}{x}\)
What would that be in numbers?
well, let's take our first two values, \(x=2~,~ y=5\)
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If you plugged those in for \(k=\dfrac{y}{x}\) what would you attain as you \(k\) value?
can u tell me the answer plz!111
Would it be 2.5?
How did you get 2.5? :P
i have no idea xD
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Objection there is no 1.7x^2 as a answer
Jhannybean
@Jhannybean
Once you figure out your k value, all you have to do is rewrite your equation in the format \(y=kx\) with your new found k value.
so what does \(k=\dfrac{5}{2} =~?\)
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