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Mathematics 14 Online
OpenStudy (anonymous):

Liberal Arts Math

OpenStudy (anonymous):

OpenStudy (misty1212):

you can use pythagoras, or you might already know this triangle

OpenStudy (misty1212):

one way is to compute \[a^2+b^2=c^2\] with \[9^2+12^2=c^2\] and solve for \(c\)

OpenStudy (misty1212):

the other thing you might could do is recognize this as a 3 4 5 right triangle, only all the sides are four times as long

OpenStudy (anonymous):

I got 225

OpenStudy (misty1212):

i guess i should say 3 times as long \[3\times 3=9\\ 3\times 4=12\\ 3\times 5=?\]

OpenStudy (anonymous):

15

OpenStudy (misty1212):

yeah it is like the last one you had, but the \(225\) is \(c^2\) so \(c=\sqrt{225}\)

OpenStudy (misty1212):

you found it!

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