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Mathematics 13 Online
OpenStudy (anonymous):

Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points.

OpenStudy (anonymous):

OpenStudy (perl):

find the points for X and U , then use distance formula

OpenStudy (perl):

X is a little bit to the right of point (2,2)

OpenStudy (anonymous):

how do u know which two points to use?

OpenStudy (perl):

it says diagonal XU, so the endpoints of the diagonal are X and U

OpenStudy (perl):

@Nnesha had a great idea, make a right triangle and XU is the hypotenuse of that right triangle

OpenStudy (anonymous):

you can use formula of distance sqrt((x1-x2)^2 + (y1-y2)^2 )

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

can someone please just find the answer Ive tried everything PLEASEEEE

OpenStudy (anonymous):

@Denu8

OpenStudy (anonymous):

@roz_mar23

OpenStudy (anonymous):

@DanJS

OpenStudy (anonymous):

@texaschic101

OpenStudy (anonymous):

Remember the distance formula? Just use that here again.

OpenStudy (anonymous):

U = (-2, 7) X = (2, 2)

OpenStudy (anonymous):

x1 = -2 x2 = 2 y1 = 7 y2 = 2

OpenStudy (perl):

X is not exactly (2,2) but we can ignore that I guess :)

OpenStudy (anonymous):

Yeah, i don't see any other way to get it @perl

OpenStudy (anonymous):

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