Mr. Barnes writes the pattern for his math class on the board.

0, 2, 8, 18, 32, ...

The class determines that each term of the pattern is twice a perfect square. Therefore, each term of the pattern is 2(n – 1)2, where n represents the term number.

Which term is equal to 800?

the 19th term
the 20th term
the 21st term
the 22nd term

Question

Mr. Barnes writes the pattern for his math class on the board.

0, 2, 8, 18, 32, ...

The class determines that each term of the pattern is twice a perfect square. Therefore, each term of the pattern is 2(n – 1)2, where n represents the term number.

Which term is equal to 800?

the 19th term
the 20th term
the 21st term
the 22nd term

anonymous · Answer

it's 2(n-1)^2, right? not times 2 at the end?

anonymous · Answer

yea

anonymous · Answer

@AlexandervonHumboldt2

anonymous · Answer

Alright, first off, set the equation equal to 800

2(n-1)^2 = 800
(n-1)^2 = 400
n-1 = squareroot(400)
n = squareroot(400) - 1

anonymous · Answer

I think that's 19

anonymous · Answer

The rest of them you just have to plug into the calculator and they work.