Mathematics
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OpenStudy (anonymous):
If tan theta =3/4 and the terminal point determined by theta is in quadrant 3, then:
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OpenStudy (anonymous):
A. cot = 4/3
B. cos = -4/5
C. sin = 3/5
D. csc = -5/3
OpenStudy (loser66):
What do you think?
OpenStudy (anonymous):
A for sure i don't know about the rest
OpenStudy (loser66):
|dw:1419386145944:dw|
OpenStudy (loser66):
that is cos and sin both are negative values, right?
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OpenStudy (loser66):
|dw:1419386241448:dw|
OpenStudy (anonymous):
cos and csc are negative values.. right?
OpenStudy (loser66):
yup
OpenStudy (anonymous):
so A is correct right?
jimthompson5910 (jim_thompson5910):
Loser66, the triangle should look like this
|dw:1419386388951:dw|
notice how one leg is on the x axis (the other leg is perpendicular to the x axis)
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jimthompson5910 (jim_thompson5910):
the reference angle is here
|dw:1419386452579:dw|
OpenStudy (anonymous):
I see
OpenStudy (loser66):
yes, my bad. Thank you Mr. Jim :)
jimthompson5910 (jim_thompson5910):
no worries
OpenStudy (anonymous):
A. cot = 4/3
B. cos = -4/5
C. sin = 3/5
D. csc = -5/3
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OpenStudy (anonymous):
I think A but what others?
jimthompson5910 (jim_thompson5910):
let's focus on just the triangle
|dw:1419386543690:dw|
jimthompson5910 (jim_thompson5910):
we are given tan(theta) = 3/4, so we can add these labels
|dw:1419386592040:dw|