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Mathematics 12 Online
OpenStudy (anonymous):

If tan theta =3/4 and the terminal point determined by theta is in quadrant 3, then:

OpenStudy (anonymous):

A. cot = 4/3 B. cos = -4/5 C. sin = 3/5 D. csc = -5/3

OpenStudy (loser66):

What do you think?

OpenStudy (anonymous):

A for sure i don't know about the rest

OpenStudy (loser66):

|dw:1419386145944:dw|

OpenStudy (loser66):

that is cos and sin both are negative values, right?

OpenStudy (loser66):

|dw:1419386241448:dw|

OpenStudy (anonymous):

cos and csc are negative values.. right?

OpenStudy (loser66):

yup

OpenStudy (anonymous):

so A is correct right?

jimthompson5910 (jim_thompson5910):

Loser66, the triangle should look like this |dw:1419386388951:dw| notice how one leg is on the x axis (the other leg is perpendicular to the x axis)

jimthompson5910 (jim_thompson5910):

the reference angle is here |dw:1419386452579:dw|

OpenStudy (anonymous):

I see

OpenStudy (loser66):

yes, my bad. Thank you Mr. Jim :)

jimthompson5910 (jim_thompson5910):

no worries

OpenStudy (anonymous):

A. cot = 4/3 B. cos = -4/5 C. sin = 3/5 D. csc = -5/3

OpenStudy (anonymous):

I think A but what others?

jimthompson5910 (jim_thompson5910):

let's focus on just the triangle |dw:1419386543690:dw|

jimthompson5910 (jim_thompson5910):

we are given tan(theta) = 3/4, so we can add these labels |dw:1419386592040:dw|

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