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Indicated expression help please? Check my potential answers?
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I think either B or D but I'm really confused
anybody? :/
you can multiply the top and bottom by the conjugate
Is that you in the pic? @JoeJoldin
\[\frac{ 5-4i }{ 8-3i } \times \frac{ 8+3i }{ 8+3i }\]
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B Do U get it?
are you happy with the answers given?
\[\frac{ 5-4i }{ 8-3i }\] \[\frac{ 5-4i }{ 8-3i }\times \frac{ 8+3i }{ 8+3i }\] to cancel the i in the denominator \[\frac{ (5*8)+(5*3i)-(4i*8)-(4i*3i) }{ (8*8)+(8*3i)-(3i*8)-(3i*3i)}\]
\[\frac{ 40+15i-32i-(-9) }{ 64+24i-24i-(-12)}\] \[\frac{ 52-17i }{ 73 }=\frac{ 52 }{ 73 }-\frac{ 17 }{ 73 }i\]
i*i=i^2=-1
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thank you so much
YW
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