can someone simply this fraction? √ ̅125 ------ √ ̅5
\[\sqrt{125} / \sqrt{5}\] That?
yes
you can start by seeing if any of those 2 nubers are perfect squares
so multlply by sqrt5/sqrt5
multiply the both top and bottom by square root 5
(sqrt125*5)/5
\[\frac{ \sqrt{125}\sqrt{5} }{ \sqrt{5}\sqrt{5} }\]
you get sqrt625/5
=25/5=5
5
awesome answer alex! you are so smart. Now to see if the actual question person knows how to do that.
lol ^
thx then could you medal me? @DanJS
@AlexandervonHumboldt2 i learned it the hard way, it's tempting to just give the answer but seriously it's actually more fun to know the person knows what they are doing..
\(\frac{\sqrt{125}}{\sqrt{5}}=\frac{5^\frac{3}{2}}{5^\frac{1}{2}}=5^{\frac{3}{2}-\frac{1}{2}}=5^\frac{2}{2}=5\)
my father teached me thats when i was 5
i think you missed the sarcastic statement by @DanJS
or \(\frac{\sqrt{125}}{\sqrt{25}}=\sqrt{\frac{125}{5}}=\sqrt{25}=5\)
Do you recall @juana02 that the square root of a number , is the same as the number to the 1/2 power? \[\sqrt{n} = n ^{1/2}\]
for example \[\sqrt{5} = 5^{1/2}\]
Or are you just doing square roots of perfect square numbers so far?
in the case where, these two expressions are equal, you can make it one square root \[\frac{ \sqrt{125} }{ \sqrt{5} } = \sqrt{\frac{ 125 }{ 5 }}\]
ok i will be on for awhile, let me know when you return @juana02
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