Mathematics
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OpenStudy (dtan5457):
More rational exponent problems...
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OpenStudy (dtan5457):
if c is not =0 simplify this equation
OpenStudy (dtan5457):
\[(2c^4-c^0)^-2\]
OpenStudy (dtan5457):
that is ^-2
OpenStudy (dtan5457):
i ended up with \[\frac{ 1 }{4c^8 }-1\]
OpenStudy (dtan5457):
which is one of the answer choices but its not the right one..what did i do wrong?
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OpenStudy (jhannybean):
\[(2c^4-c^0)^{-2}\]distribute the \(\color{red}{-2}\)
OpenStudy (dtan5457):
i did but obviously i did it wrong
OpenStudy (jhannybean):
haha no no, whichever method you prefer.
OpenStudy (dtan5457):
2^-2=1/4
OpenStudy (dtan5457):
c^4 times ^-2=1/c^8
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OpenStudy (dtan5457):
probably the -c^0 i did an error somewhere..
OpenStudy (jhannybean):
\[(2c^4-c^0)^{-2} \implies \frac{1}{(2c^4-c^0)^2}\]
OpenStudy (jhannybean):
2 ways you can do this.
1. \((2c^4-c^0)^{2} = (2c^4 -c^0)(2c^4-c^0)\)
2. \((2c^4-c^0)^{2} = (2c^4)^2 - (c^0)^2\)
OpenStudy (dtan5457):
i pretty much did it the 2nd way or attempted the 2nd way
OpenStudy (jhannybean):
Let's do it both.
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OpenStudy (dtan5457):
start with the 2nd :D
OpenStudy (jhannybean):
Im just going to show you how to simplify the expression, you should now know that this expression is positive because it is in the denominator.
OpenStudy (jhannybean):
Like @Nnesha mentioned earlier :P
OpenStudy (dtan5457):
alright.
OpenStudy (dtan5457):
2c4^2=4c^8?
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OpenStudy (jhannybean):
Good.
OpenStudy (dtan5457):
now is it -(c^0)^2?
OpenStudy (jhannybean):
yes
OpenStudy (dtan5457):
is that just -1?
OpenStudy (jhannybean):
Good, yep
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OpenStudy (dtan5457):
4c^8-1?
OpenStudy (jhannybean):
Yep.
OpenStudy (jhannybean):
So you would have \[\frac{1}{4c^8 -1}\]
OpenStudy (dtan5457):
not an answer for some reason.
OpenStudy (jhannybean):
Do you have answer choices?
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OpenStudy (dtan5457):
The answer only comes if you foil (2c^4-c^0)
OpenStudy (dtan5457):
that's weird..huh..
OpenStudy (jhannybean):
Let's see.
OpenStudy (dtan5457):
(2c^4−c^0)2=(2c^4)2−(c^0)2
OpenStudy (dtan5457):
i don't think that is possible?
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OpenStudy (dtan5457):
because wouldn't that be like
(5+5)^2=100
5^2+5^2=50?
OpenStudy (jhannybean):
\[(2c^4-c^0)^{2} = (2c^4 -c^0)(2c^4-c^0) = 4c^8 -(2c^4\cdot c^0)-(2c^4 \cdot c^0)+1\]
OpenStudy (dtan5457):
4c^8-4c^4+1
OpenStudy (dtan5457):
that is the correct answer.
OpenStudy (dtan5457):
i guess i have to foil it
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OpenStudy (dtan5457):
well to be specific
1 over 4c^8-4c^4+1
OpenStudy (dtan5457):
is the answer
OpenStudy (jhannybean):
Yeah, that makes sense... because you don't want to have negative exponents in yoru answer.
OpenStudy (jhannybean):
\[4c^8 -(2c^4\cdot c^0)-(2c^4 \cdot c^0)+1 = 4c^8 -2c^{4-0} -2c^{4-0} +1 = 4c^8 -4c^4+1\]
OpenStudy (dtan5457):
yess.
thank you :)