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Mathematics 13 Online
OpenStudy (dtan5457):

More rational exponent problems...

OpenStudy (dtan5457):

if c is not =0 simplify this equation

OpenStudy (dtan5457):

\[(2c^4-c^0)^-2\]

OpenStudy (dtan5457):

that is ^-2

OpenStudy (dtan5457):

i ended up with \[\frac{ 1 }{4c^8 }-1\]

OpenStudy (dtan5457):

which is one of the answer choices but its not the right one..what did i do wrong?

OpenStudy (jhannybean):

\[(2c^4-c^0)^{-2}\]distribute the \(\color{red}{-2}\)

OpenStudy (dtan5457):

i did but obviously i did it wrong

OpenStudy (jhannybean):

haha no no, whichever method you prefer.

OpenStudy (dtan5457):

2^-2=1/4

OpenStudy (dtan5457):

c^4 times ^-2=1/c^8

OpenStudy (dtan5457):

probably the -c^0 i did an error somewhere..

OpenStudy (jhannybean):

\[(2c^4-c^0)^{-2} \implies \frac{1}{(2c^4-c^0)^2}\]

OpenStudy (jhannybean):

2 ways you can do this. 1. \((2c^4-c^0)^{2} = (2c^4 -c^0)(2c^4-c^0)\) 2. \((2c^4-c^0)^{2} = (2c^4)^2 - (c^0)^2\)

OpenStudy (dtan5457):

i pretty much did it the 2nd way or attempted the 2nd way

OpenStudy (jhannybean):

Let's do it both.

OpenStudy (dtan5457):

start with the 2nd :D

OpenStudy (jhannybean):

Im just going to show you how to simplify the expression, you should now know that this expression is positive because it is in the denominator.

OpenStudy (jhannybean):

Like @Nnesha mentioned earlier :P

OpenStudy (dtan5457):

alright.

OpenStudy (dtan5457):

2c4^2=4c^8?

OpenStudy (jhannybean):

Good.

OpenStudy (dtan5457):

now is it -(c^0)^2?

OpenStudy (jhannybean):

yes

OpenStudy (dtan5457):

is that just -1?

OpenStudy (jhannybean):

Good, yep

OpenStudy (dtan5457):

4c^8-1?

OpenStudy (jhannybean):

Yep.

OpenStudy (jhannybean):

So you would have \[\frac{1}{4c^8 -1}\]

OpenStudy (dtan5457):

not an answer for some reason.

OpenStudy (jhannybean):

Do you have answer choices?

OpenStudy (dtan5457):

The answer only comes if you foil (2c^4-c^0)

OpenStudy (dtan5457):

that's weird..huh..

OpenStudy (jhannybean):

Let's see.

OpenStudy (dtan5457):

(2c^4−c^0)2=(2c^4)2−(c^0)2

OpenStudy (dtan5457):

i don't think that is possible?

OpenStudy (dtan5457):

because wouldn't that be like (5+5)^2=100 5^2+5^2=50?

OpenStudy (jhannybean):

\[(2c^4-c^0)^{2} = (2c^4 -c^0)(2c^4-c^0) = 4c^8 -(2c^4\cdot c^0)-(2c^4 \cdot c^0)+1\]

OpenStudy (dtan5457):

4c^8-4c^4+1

OpenStudy (dtan5457):

that is the correct answer.

OpenStudy (dtan5457):

i guess i have to foil it

OpenStudy (dtan5457):

well to be specific 1 over 4c^8-4c^4+1

OpenStudy (dtan5457):

is the answer

OpenStudy (jhannybean):

Yeah, that makes sense... because you don't want to have negative exponents in yoru answer.

OpenStudy (jhannybean):

\[4c^8 -(2c^4\cdot c^0)-(2c^4 \cdot c^0)+1 = 4c^8 -2c^{4-0} -2c^{4-0} +1 = 4c^8 -4c^4+1\]

OpenStudy (dtan5457):

yess. thank you :)

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