Which is the equation of a line that is parallel to 2x+5y=4 and goes through the point (5,-4) A) Y= -2/5x-6 B)Y= -2/5x+2 C)Y= 2/5x-6 D)Y= -2/5x-2
ok, it would probably be easiest to put the equation into the slope intercept form to begin y = mx + b, where m is the slope of the line
5y=2x+4?
almost, you want to subtract 2x on both sides, so you will have a -2x
5y = -2x + 4
oh yeah lol okay got it. Now what?
divide everything by 5
you want y = .....
y=-2/5-2?
where did the x go? and 4 divided by 5 is, 4/5
i accident divded the 4 by -2 lol
thats ok, so this is what you get for the given line in the slope intercept form \[y = \frac{ -2 }{ 5 }x + \frac{ 4 }{ 5 }\]
But my pretest doesn't give me that for any of my answers.. :(
that is just the given line, we now need to use information from that to find a different line with the point they gave you
oh okie dokie how does one do that?
The key point here, is that the slope of a parallel line , will be the same slope m = -2/5 in the y = m*x + b for y = (-2/5)x + 4/5
we now have the slope (-2/5) and a point (x,y) = (5,-4) given in the problem.
Point-Slope form of a line, Given slope: m = -2/5 Point : (x1, y1) = (5, -4) Fill in for this point slope equation: y - y1 = m*(x - x1)
I got 9=m(-7) is that riht?
Point - slope form of a line y - y1 = m*(x - x1) put in: m = -2/5 x1 = 5 y1 = -4
y - (-4) = (-2/5)(x - 5)
all i did was put the numbers in the equation
You can now simplify that, and it should look like one of the answers, a line parallel to the given line
y - (-4) is the same as y + 4 y + 4 = (-2/5)*(x-5)
distributing the -2/5 into the (x-5) you get \[y + 4 = \frac{ -2 }{ 5 }x + 5\frac{ 2 }{ 5 }\]
\[y + 4 = \frac{ -2 }{ 5 }x + 2\]
take away 4 from both sides \[y = \frac{ -2 }{ 5 }x -2\]
so y=-2/5-6?
no -2
-2/5-2
(-2/5)x - 2
yass! thank you bro!
The things you need to remember: Slope intercept: Y = m*X+b m= slope, b = y-axis intercept Point -slope form y - y1 = m(x-x1) m=slope , (x1,y1) is a point on the line A line parallel to a given line will have the same slope, m
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