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Mathematics 17 Online
OpenStudy (ineedhelp10):

help please

OpenStudy (ineedhelp10):

What are the solutions of 3x^2-4x+8=0 ?

OpenStudy (solomonzelman):

\(\large\color{black}{ (-4)^2-4(3)(8)<0 }\)

OpenStudy (ineedhelp10):

lol hi again

OpenStudy (solomonzelman):

hello:) have you learned about imaginary number \(\large\color{black}{ i }\) ?

OpenStudy (ineedhelp10):

yeah

OpenStudy (solomonzelman):

so, I guess, we should then proceed. \(\large\color{black}{ (-4)^2-4(3)(8) ~~~\Rightarrow ~~~16-96~~~\Rightarrow-80 }\)

OpenStudy (solomonzelman):

I tested the discriminant, \(\large\color{black}{ -80 }\) is not an "imaginary perfect square" (excuse me for this term)

OpenStudy (solomonzelman):

So, use the quadratic formula.

OpenStudy (solomonzelman):

\(\normalsize\color{ slate }{\Huge{\bbox[5pt, lightcyan ,border:2px solid black ]{ \LARGE{x=~} \huge{ \frac{-\color{magenta}{b} \pm\sqrt{ \color{magenta}{b} ^2-4 \color{blue}{a} \color{red}{c}}}{2 \color{blue}{a}} }~ }}}\) when the equation is \(\LARGE\color{black}{ \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0 }\).

OpenStudy (ineedhelp10):

and i got \[4+-\sqrt{-80}/6 \]

OpenStudy (solomonzelman):

yes, it is \(\large\color{black}{ \frac{\LARGE 4\pm\sqrt{80} }{\LARGE 6} }\)

OpenStudy (solomonzelman):

I mean \(\large\color{black}{ \frac{\LARGE 4\pm\sqrt{-80} }{\LARGE 6} }\)

OpenStudy (ineedhelp10):

yeah that's what i got too

OpenStudy (solomonzelman):

this is not it though

OpenStudy (ineedhelp10):

yeah i get that

OpenStudy (solomonzelman):

Okay, \(\large\color{black}{ \sqrt{-80}=\sqrt{-1}\times \sqrt{16} \times \sqrt{5} }\)

OpenStudy (solomonzelman):

So, \(\large\color{black}{ \sqrt{-80} }\) can be re-written as?

OpenStudy (ineedhelp10):

as radical 16 and radical 5 no?

OpenStudy (solomonzelman):

my connection sucks

OpenStudy (solomonzelman):

~ \(\large\color{black}{ \sqrt{-1}=i }\) (definition of the imaginary number \(\large\color{black}{i }\) ) ~ \(\large\color{black}{ \sqrt{16}=4 }\) ~ \(\large\color{black}{ \sqrt{5}=\sqrt{5} }\) (can't be reduced)

OpenStudy (solomonzelman):

you know these 3 things, don't you?

OpenStudy (ineedhelp10):

oh okay so then would it be \[2+-4i \sqrt{5}\div3 \]

OpenStudy (ineedhelp10):

excuse the way i did it lol

OpenStudy (solomonzelman):

you got this correctly, that: \(\large\color{black}{ \sqrt{-80}=\pm4i \sqrt{5} }\)

OpenStudy (solomonzelman):

\(\large\color{black}{ \frac{\LARGE 4 ~\pm~4i\sqrt{5} }{\LARGE 6} }\)

OpenStudy (solomonzelman):

then reduce this fraction.

OpenStudy (ineedhelp10):

yeah i got 2/3 for the fraction

OpenStudy (solomonzelman):

\(\large\color{black}{ \frac{\LARGE 4 ~\pm~4i\sqrt{5} }{\LARGE 6} }\) \(\large\color{black}{ \frac{\LARGE 2 ~\pm~2i\sqrt{5} }{\LARGE 3} }\)

OpenStudy (ineedhelp10):

the only option closest to that, that i have is in -2 tho

OpenStudy (solomonzelman):

are you sure you didn't have any typos in the question?

OpenStudy (ineedhelp10):

nope its right

OpenStudy (solomonzelman):

well, if the equation is: \(\large\color{black}{ 3x^2-4x+8=0}\) then, above are the solutions for it.

OpenStudy (ineedhelp10):

oh ok then, it was probably a mistake from my teacher. thank you anyway tho!

OpenStudy (solomonzelman):

yw

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