Question

dy/dx = 2y^2 and if y = -1 when x = 1. then when x = 2, y=?

Answer 1

dy/y^2 = 2*dx, now integratin both sides
-1/y = 2x + C
when x = 1, y=-1
-1/-1 = 2*1 + C
1 = 2 + C
C = -1, so...
-1/y = 2x -1
When x=2:
-1/y = 4 -1
-1/y = 3
y = -1/3

Answer 2

but there is no x in the derivative....

Answer 3

oh, integration on both sides, didn't think of that

Answer 4

yeah, I will make sure to include this type of problems as well, ty

Answer 5

:)

Answer 6

I thought it was one of those, when the differential dx=... and f(x)=... find dy,. Looked at it wrong.....

Answer 7

\(\huge\bf\color{seagreen}{Welcome~to~Openstudy!~:)}\) @audiq7

Answer 8

teal