Another answer check - What is the range of the following function f(x) = sqrt 2x +3 with the domain -1, 0, 1, 2, 3, 4 ,5? - My answer in the comments (also better problem view).

Question

anonymous · Answer

Function: $$f(x) = \sqrt{2x+3}$$
My answer, range:$$2, 0, \sqrt{5}, \sqrt{7}, 3, \sqrt{12}, \sqrt{13}$$

dtan5457 · Answer

Looks like all you have to do is plug in your domain (x) into your function, but x=4
y=sqrt 11, if I'm not mistaken..?

dtan5457 · Answer

x=-1
y=1

x=0
y=sq rt 3

dtan5457 · Answer

everything looks about right

dtan5457 · Answer

If this question did not have a set domain

that range of that function would be all real non-negative numbers

anonymous · Answer

Sorry, I was afk for a bit. Can you show the solving process?

dtan5457 · Answer

Well I mean it's exactly what you did..plug the x value into the function. I just see that you plugged x=4, and x=-1 wrong

anonymous · Answer

So it's sqrt 1 for x=-1 and sqrt 11 for x=4?

dtan5457 · Answer

yeah.

anonymous · Answer

okay, thanks :D