Question

10.The diagram shows part of the graph of y=(x+p)(x+q),where p and q are constans. @hartnn @Directrix @ganeshie8 @iambatman @Michele_Laino

Answer 1

Find the value of p,of q and of k.

Answer 2

please you have to solve the subsequent conditions:
\[0=(p-1)(q-1),0=(p+5)(q+5)\]
the first since point (-1,0) belongs to your function,
and the second, because point (5,0) also belongs to your function.
Please try tosolve those equations for p and q

Answer 3

okay :)

Answer 4

p=1,q=1 and p=-5,q=-5 like this @Michele_Laino

Answer 5

sorry, I think no,
for example, from first condition I get p=1 and q can have any value

Answer 6

then I substitute p=1 into the second condition and I get 0=6*(q+5), from which q=-5
so the solution is:
p=1 and q=-5

Answer 7

please note that you have only one function in your graph!

Answer 8

so your function is:
\[f(x)=(x+1)(x-5)\]

Answer 9

k=-5

Answer 10

corret? @Michele_Laino

Answer 11

that's right!

Answer 12

\[y=k\]

Answer 13

\[k=(x+p)(x+q)\]

Answer 14

\[k=(1)*(-5)\]

Answer 15

\[k=(-1)(5)\]

Answer 16

yes!

Answer 17

k=-5

Answer 18

thnx a lot @Michele_Laino

Answer 19

thanks! @MARC_

Answer 20

:)