Question

two years ago ,father was three times as old as his son and two year hence,twice his age will be equal to five times that of his son.find the peresent ages.

Answer 1

please help

Answer 2

I am working on some equations now.

Answer 3

ok

Answer 4

I started with this but something is not right.
Maybe you can see the error in the set-up of the equations.

Let F be the father's age today
Let S be the son's age today

Father's age 2 years ago: F - 2
Son's age 2 years ago: S - 2

So, F - 2 = 3*(S - 2)

and ...

Answer 5

Father's age 2 years from today: F + 2
Son's age 2 years from today: S + 2

F + 2 = 5*(S + 2)

Answer 6

F - 2 = 3*(S - 2)
F + 2 = 5*(S + 2)
============
Solving these simultaneously yields F = - 22 and S = -6 which cannot be correct.

I need to re-read the question.

Answer 7

>> two year hence
I assume that is two years from today and not two years from two years ago because that would be today. :)

Answer 8

wait i m telling u the answer

Answer 9

28 yrs,14yrs

Answer 10

I am trying to re-do my equations. Something is wrong with my work.

Answer 11

in my school note book two years ago age is taken as
father- 3x+2
son- x+2
but why this happen i dont know

Answer 12

two years ago ,father was three times as old as his son and two year hence,twice his age will be equal to five times that of his son.find the peresent ages.

Let fathers' present age is x and son's age be y

2 years ago, fathers' age was: x-2 = 3y
2 years after, father's age will be : x + 2 => 2(x+2) = 5y

Answer 13

hmm.. something is wrong :D

Answer 14

>>in my school note book two years ago age is taken as father- 3x+2
son- x+2

father-> 3x+2 ==> This is father's age today, then

son->x+2 ==> This is son's age today, then

Answer 15

oops.. got it!

2(x+2) = 5(y+2)
x-2 = 3(y-2) => x -2 = 3y - 6 => x = 3y -4

2(3y-4+2) = 5(y+2)
2(3y-2) = 5(y+2)
6y - 4 = 5y + 10
y = 14

Answer 16

but why we take +2

Answer 17

in question there is ago

Answer 18

Directrix will help u out. :)

Answer 19

vo to pta ni kha gya