Question

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).
y = -one third x - 6
y = -one third x - 14
y = 3x - 6
y = 3x - 14
@TheSmartOne

Answer 1

First rearrange the equation to slope-intercept form.

3x - y = -3

Subtract 3x to both sides:

-y = -3x - 3

Multiply -1 to both sides:

y = 3x + 3

Now it's in the form of y = mx + b, where m is the slope. So what's the slope here? @autinregister