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Mathematics 19 Online
OpenStudy (anonymous):

What would be the domain and range of y=(x-3)^2+2 and the domain and range of its inverse?

OpenStudy (anonymous):

a parabola

OpenStudy (anonymous):

Yep - and the vertex is at (3, 2), right?

OpenStudy (anonymous):

For any polynomial, the domain is all real numbers. In interval notation, this looks like (-infinity, infinity) Now all we need to do is find the range.

OpenStudy (anonymous):

|dw:1420000300720:dw|The graph looks something like this. So the range is [3, infinity)

OpenStudy (anonymous):

Oops, [2, infinity)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

However, we are asked for the domain and range of the inverse, which means we need to switch the domain and range. D: [2, infinity) R: (-infinity, infinity)

OpenStudy (anonymous):

*Technically, this function doesn't have an inverse, because it isn't 1-1

OpenStudy (anonymous):

The most correct thing you could say is that the domain is [2, infinity) and the range is (-infinity, infinity), and that the function doesn't have an inverse. If you had an invertible function, you could switch the domain and range (because you are just switching x and y)

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