Question

Help me please solve this question..question at below

Answer 1

\[\lim_{x \rightarrow \infty}(1/x^2-\cos3x/x^2)\]

Answer 2

nope

Answer 3

i'm afraid limits are not my strong point

Answer 4

limit of the first term is zero..

Answer 5

i am sorry the limit is zero

Answer 6

wait, you mean, \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~0}\frac{ 1-\cos(3x)}{x^2 }}\) ?

Answer 7

ya..thats right.i m sorry

Answer 8

okay, so the fastest thing I see is to use L'H'S.

Answer 9

(yes, it is in indeterminate form, 0/0 )

Answer 10

so its x--> 0 not infinity?

Answer 11

yes, it is what I poster, cwcr

Answer 12

There are couple of methods that can be used without LH too,
one of them involves multiplying
\(\Large 1+\cos 3x \)
in numerator and denominator :)

Answer 13

oh ok

Answer 14

i got the answer 9/2..correct me if i m wrong..i solve it using l hospital rule

Answer 15

yes

Answer 16

you used L'h"s twice ? :D

Answer 17

its correct! :)

Answer 18

ya

Answer 19

very good!

Answer 20

I haven't considered solving the original problem you posted....

Answer 21

i am asking to much question..lol.final exam calculus one more day to go..haha

Answer 22

you are asking fine,... you can ask as many questions as you want as long as you ask 1 question per post, and don't violate the rules.

Answer 23

I was also going to use LHS twice if I were yopu, it is a very fast method in this case.

Answer 24

are you really a professor dude?

Answer 25

Nope, do I look like one?

Answer 26

I mean asides from the title

Answer 27

I am not even a matematician

Answer 28

a little bit..lol

Answer 29

:)

Answer 30

alrigth igtg, yw