FAN AND MEDAL. What is the 9th term of the geometric sequence where a1 = -8 and a6 = -8,192?
A. -327,680 B. -393,216 C. -458,752 D. -524,288
\[a_n = a_1 q^{n-1}\], so... \[a_6 = a_1 q^{5}\]\[-8.192 = -8 q^{5}\]\[q = 1.00475\] Now, just find the a_9
please note that: \[a _{6}=a _{1}*q ^{5}\]whre q is the constant f yr geometric sequence
Do you understand?
oops...of your geometric...
No.
The geometric sequency have the form: \[a_n = a_1 q^{n-1}\]
if we know the ratio "q" and the first element of the sequency "a_1", we can calculate any element of this sequency
please substitute your umerical data ino the subsequent relation: \[a _{6}=a _{1}*q ^{5}\] and find q^5, please!
you know the first element "a_1" and element "a_6", using the equation above, you need to find the ratio of the sequency, for just then, find the value of "a_9" by: \[a_9 = a_1 q^{8}\]
got it?
I'm actually confused.
have u ever seen the equation i showed you?
In what exactly you got confused?
No, I don't think I've ever seen the equation and I'm just not awesome at math.
Ok, let's deduce the formula, suppose we have the element one of the sequency \(a_1\) and we what to find the second element of the sequency, then: \(a_2 = a_1*q\), the third element will be \(a_3 = a_2 * q\), and so on... For the n-th element: \(a_n = a_{n-1} * q = a_{n-2}*q^2 = ... = a_1*q^{n-1}\)
It's multiple choice on a timed test so honestly I'm just gonna guess at this point. Thanks for your help though.
q=1.00475 a1 = -8 a9=a1 q^8 a9=-8*(1.00475)^8 slve u will get answer
Thanks!
did u get the answer
Yeah, I did. It's -524,288 right?
whats the value of this (1.00475)^8 ???
I've already submitted the test so if it isn't right, then oh well.
just say whats the value of this (1.00475)^8 ???
1.0386377874
I got the right answer so it's all good.
after multiplying1.0386377874 with -8 the answer is ??
There's no point to this anymore, the final answer is -524,288. That's what I needed.
ok
Thanks for your help!
i didnt get the answer
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