The area of a square garden is 128 m². How long is the diagonal? A. 8 m B. 4 times the square root of 2 C. eight times the square root of 6 D. 16 m My guess is D
well take the square root of the area to find the side length. then use pythagoras to find the diagonal length
\[S ^{2}=128\] Solve for S and the use the pythagorean to find the diagonal
\[\sqrt{2S ^{2}}=D\]
Not to sound moronic but whats pythagoras?
Like is it a formula?
pythagoras is a mathematician who developed the pythagorean theorem to solve for the hypotenuse of a right triangle. the formula you will use is of the form \[a ^{2}+b ^{2}=c ^{2}\] where a and b are the sides of the legs. I have reduced the equation further for your particular case with the equation above
ok... to start you need to know |dw:1420057537175:dw| using thr diagram and applying pythagoras' theorem to find the diagonal \[d^2 = l^2 + l^2\] which becomes \[d^2 = 128 + 128\] can you simplify this?
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