Question

Expand The Logarithm Below Show Your Work.

Answer 1

\[\log_{8}8\sqrt{3a ^{5}} \]

Answer 2

@cwrw238

Answer 3

same first step as the one I messed up on\[\log(ab)=\log a+\log b\]

Answer 4

I know you have to separate them first.

Answer 5

My problem is the square root.

Answer 6

next write the radical as a fractional exponent
what exponent is square root?

Answer 7

\[x^{1/2}\]

Answer 8

\[\log_{8}8+\log_{8}(3a^{5})^{1/2} \] ?

Answer 9

now what?

Answer 10

what do you think the value of log8 8 is?

Answer 11

8^1 = 8
so log of 8 to the base 8 is 1

Answer 12

1

Answer 13

\[1+\log_{8}(3a ^{5})^{1/2} \]

Answer 14

yes

Answer 15

now I 'm not sure if they want you to change the second term to the form a log8 b or not

Answer 16

what would that look like?

Answer 17

I'll right them both.

Answer 18

this is just for understanding.

Answer 19

that is 1 + (1/2) log8 3a^5

Answer 20

Thanks and Happy New Years.

Answer 21

thanks Happy New Year to you also