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Mathematics 17 Online
OpenStudy (anonymous):

4.Given the function

OpenStudy (anonymous):

\[f:x \rightarrow \frac{ 2x }{ x-1 },x1\]

OpenStudy (jhannybean):

Doesn't really make sense.

OpenStudy (alexandervonhumboldt2):

yeagh

OpenStudy (anonymous):

b) state the value of x such that f^-1 does not exist.

OpenStudy (alexandervonhumboldt2):

so you cannot divide by 0 right

OpenStudy (alexandervonhumboldt2):

so we need to make denominator 0

OpenStudy (alexandervonhumboldt2):

x-1=0 x?

OpenStudy (anonymous):

x=1

OpenStudy (anonymous):

so it will be 2? @AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

yes so the function doesnt exist where x=1

OpenStudy (anonymous):

Thnx @AlexandervonHumboldt2

OpenStudy (jhannybean):

Yeah, that seems correct.

OpenStudy (alexandervonhumboldt2):

txh you too

OpenStudy (jhannybean):

You will find a vertical asymptote at x=1. That is where the function dne.

OpenStudy (anonymous):

Thnx @Jhannybean

OpenStudy (jhannybean):

Np

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