Question

In a second-order reaction (one that is second order in one reactant), cutting in half the concentration of that reactant will have what effect on the reaction rate?

Answer 1

The reaction rate will remain the same.
The reaction rate will double.
The reaction rate will decrease by a factor of two.
The reaction rate will increase by a factor of four.
The reaction rate will decrease by a factor of four.

Answer 2

if it's second order with respect to that reactant, what happens when you take \(\frac{1}{2}\) and square it?