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Mathematics 20 Online
OpenStudy (kj4uts):

For this function (attached below) what is the maximum value? Please explain answer. Thank you!

OpenStudy (kj4uts):

OpenStudy (jhannybean):

I thought I had messed up.

OpenStudy (zzr0ck3r):

what is the derivative?

OpenStudy (jhannybean):

\[y=-3+4\cos\left(\frac{5\pi}{6} (x+4)\right)\]This function follows the format \(\sf y=A+B\cos(Cx)\) where the Maximum is: M = A+B. \(\therefore\) M = 4 -3 =1 http://www.cliffsnotes.com/math/trigonometry/graphs-of-trigonometric-functions/graphs-sine-and-cosine

OpenStudy (zzr0ck3r):

I am not sure this is in that form

OpenStudy (zzr0ck3r):

we can get the inside to be a constant times x

OpenStudy (zzr0ck3r):

but that's the right answer:)

OpenStudy (jhannybean):

How did you find it?

ganeshie8 (ganeshie8):

\[-1\le \cos(\clubsuit)\le 1\] \[-4\le 4\cos(\clubsuit)\le 4\] \[-3-4\le-3+ 4\cos(\clubsuit)\le -3+ 4\] \[-7\le-3+ 4\cos(\clubsuit)\le 1\]

OpenStudy (zzr0ck3r):

like that^

OpenStudy (zzr0ck3r):

I don't know that formula, but you wrote Cx and we had c(x+b) they are not the same form, the first one is called linear and the second one is called affine. I was not saying you are wrong or anything like that. I was just saying it did not match the form. p.s. It may be confusing what I wrote because people often call y=mx+b a linear equation, but its not(unless b=0). linear equations must go through the origin.

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