A mountain climber of mass m hangs onto a rope to keep from sliding down a smooth, ice-covered slope. Find a formula for the tension in the rope when the slope is inclined at an angle θ above the horizontal. Check your results in the limits θ = 0 and θ = 90.

Question

anonymous · Answer

http://snag.gy/6sVEa.jpg

michele_laino · Answer

I think that the module of tension "T" exerted by the rope on the climber is equal to:
$$T=m*g*\sin \theta $$
since this is the situation of your exercise:
|dw:1420300505315:dw|
since the climber is blocked, the by the first principle of Dynamics, we have$$T=m*g*\sin $$