Question

10.The diagram shows part of the graph of y=(x+p)(x+q),where p and q are constants.Find the value of p,of q and of k. @ganeshie8

Answer 1

diagram ?

Answer 2

Look at the graph, what are the x values at which the graph cuts x axis ?

Answer 3

-1 and 5

Answer 4

Yes!

Answer 5

y=(x+p)(x+q)

setting this equal to 0 and solving also gives the x intercepts, yes ?

Answer 6

(x+p)(x+q) = 0

(x+p) = 0 , (x+q) = 0
x = -p , x = -q

Answer 7

so -p and -q must equal -1 and and 5 yes ?

Answer 8

yep

Answer 9

if we let -p = -1
then -q = 5

Answer 10

that gives p = 1 and q = -5

Answer 11

can we do like this?
-p=5
-q=-1

Answer 12

@ganeshie8

Answer 13

yes we can do that too

Answer 14

that gives you p = -5 and q = 1

Answer 15

\(\bf\huge\color{#ff0000}{T}\color{#ff2000}{h}\color{#ff4000}{a}\color{#ff5f00}{n}\color{#ff7f00}{k}~\color{#ffaa00}{Y}\color{#ffd400}{o}\color{#bfff00}{u}\color{#4600ff}{!}\color{#6800ff}{!}\color{#8b00ff}{!}\) @ganeshie8

Answer 16

np :) whaat about the value of \(\large k\) ?

Answer 17

\(\tt \begin{align} \color{black}{
\text{for finding k,put x=0}
}\end{align}\)

Answer 18

k=-5

Answer 19

Thnx @ganeshie8 @mathmath333

Answer 20

i know the value of k.i was only confuse about the value p and q but know i get it.Thnx.