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3.Find the range of values of x of each of the following. @ganeshie8
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a)\[12>x(x-4)\] b)\[x(7-5x)>2\]
a)\[x^2-4x-12>o\]
careful about the inequality
\[(x-6)(x+2)>0\]
hold up
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\[12>x(x-4)\] subtracting 12 gives \[0 >x(x-4)-12\] yes ?
yep
go to right side of that and look at it
\[\large x(x-4)-12 \color{red}{<} 0\]
\[\large x^2-4x-12 \color{red}{<} 0\]
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\[\large (x-6)(x+2) \color{red}{<} 0\]
now think of how the graph of parabola with intercepts 6 and -2 looks like
opens upward
yes! draw a rough sketch
|dw:1420358166381:dw|
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|dw:1420358214238:dw|
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