Question

Determine the quadrant when the terminal side of the angle lies according to the following conditions: sin (t) < 0, csc (t) > 0.

Answer 1

How? \(csc (t)=\dfrac{1}{sin(t)}\) and 1>0 always, sin (t) <0, how can csc (t) >0 ??

Answer 2

sorry. i cant help. i didn't write the problem and i dont understand either.

Answer 3

since:
\[\csc t= \frac{ 1 }{ \sin t }\]
so you are searching for a quadrant in which sin t>0 and sin t<0.
Is it possible?