I'm solving using a substitution but it doesn't make sense, can someone help me? 2x+2y=38 y=x+3
\[2x+2(y)=38\]\[(y)=x+3 \] \[2x+2(x+3)=38\]
\(\large\color{slate}{ 2x+2y=38 }\) \(\large\color{slate}{ y=x+3 }\) see the part, I am labeling in red, \(\large\color{slate}{ \color{red}{x+3} }\) ? (according to your first equation) it is equivalent to \(\large\color{slate}{ y }\) So this is what we do to the first equation: \(\large\color{slate}{ 2x+2y=38 }\) substitution: \(\large\color{slate}{ 2x+2(\color{red}{x+3} )=38 }\)
like this. Makes sense?
After the substitution is plugged in, do I sole it then?
Find what x is. Then once you know what x is, plug it back in to either equation, and you can find what y is.
*solve
Yeah, once you solve for x, you can solve for y by plugging x back into either equation, and simplifying the algebra.
I got 8 for x.
x = 8 is correct
Can you find y?
I solve y the same way I solved x?
You could do that I suppose
11?
Yes. A short way to find y is: You know x is 8. You also know y=x+3, or y is 3 greater than 8. So y is equal to 11
So my answer would be: x=8 y=11
Yes
Thanks.
You can plug it in to either equation to check
2(8)+2(11)=38
I was stuck when finding y because the equation was already set I didn't know if should start over and find y or just leave it how it was to find y.
You could do both
Start with: 2x+2y=38 y=x+3 You know how to find x from earlier. You can use the same method to find y, you just have to rearrange the second equation to become y-3=x
2(x)+2y=38 and y-3=(x) Combine. 2(y-3)+2y=38 And you can find y
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