Question

Help!

Answer 1

\[\sqrt[3]{-1}\]

Answer 2

wow

Answer 3

how much is -1*-1

Answer 4

\[-1*-1\]

Answer 5

When I do this on my calculator, the answer says its \[\frac{ 1 }{2 }+\frac{ \sqrt{3} }{ 2}*i\]

Answer 6

I don't understand how this is possible...

Answer 7

dude answer is -1!!

Answer 8

u got that??

Answer 9

-1x-1x-1

Answer 10

yes...

Answer 11

so next part

Answer 12

what u see there is complex number

Answer 13

under complex number.....which u will learn later.............i=\[-1^{(1/2)}\]

Answer 14

I already learned complex numbers

Answer 15

using complex numbers we equate negative square roots which aren't defined under real numbers......

Answer 16

oh

Answer 17

in that case turn the equation into i form

Answer 18

what do u get??

Answer 19

\[like~i^{2}=-1\]

Answer 20

I also tried this on the calcultor and got \[(\frac{ 1 }{ 2 }+\frac{ \sqrt{3} }{ 2 }*i)^{3}=-1\]

Answer 21

it is correct

Answer 22

i still don't get this

Answer 23

then u have to use the exponential notation

Answer 24

of complex numbers

Answer 25

it is of the form a+iB

Answer 26

you can remember that: \(\Large\color{teal}{ \sqrt[\LARGE \rm odd~number]{-1} =-1 }\).

Answer 27

talking about an integer odd number of course

Answer 28

@SolomonZelman I think he wants to know how the calculator got that answer

Answer 29

commn

Answer 30

A+iB>>> A=1/2 and B=\[3^{1/2}/2\]

Answer 31

getting it.......??? If u know Complex numbers u will understand me

Answer 32

i honestly don't know how to do that in a calculator my teacher teaches us without calcs so we do this by hand it just like \[\left( \sqrt{-1} \right)^{\frac{ 3 }{ 1 }}\] which would look like \[\left( \sqrt[3]{-1} \right)^{1}\] i think. I might have the first equation exponent backwards