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Mathematics 8 Online
OpenStudy (anonymous):

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jimthompson5910 (jim_thompson5910):

correct since the circumcenter is formed from intersecting the perpendicular bisectors of the three sides of the triangle

OpenStudy (anonymous):

Thanks, would you say it's wrong to attach another question in this thread?

jimthompson5910 (jim_thompson5910):

I guess one more doesn't hurt since this problem was short, but ideally each problem gets its own post

jimthompson5910 (jim_thompson5910):

i don't mind it though

jimthompson5910 (jim_thompson5910):

did you find the lengths of the four sides? and the lengths of the diagonals?

jimthompson5910 (jim_thompson5910):

find the lengths of these segments EF FG GH HE use the distance formula

jimthompson5910 (jim_thompson5910):

yes you have a square

OpenStudy (anonymous):

GH= 17. 088 Now I'm confused, why isn't it equal?

OpenStudy (anonymous):

HE= 10

jimthompson5910 (jim_thompson5910):

wait, how did you get to C when you got GH= 17. 088 and HE= 10

jimthompson5910 (jim_thompson5910):

GH= 17. 088 and HE= 10 are incorrect

OpenStudy (anonymous):

I got 6 for the first two segments and concluded they were all equal.

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