Question

PLEASE HELP ME

Answer 1

just writing to have a vision of them.
\(\large\color{slate}{ 5x-y=27 }\)
\(\large\color{slate}{ 2x+3y=-13 }\)

Answer 2

ok

Answer 3

What you can do is:
rearrange the first equation to y=....
(solve for y in the first equation)

Answer 4

(the steps for this rearrangement:
1) add y to both sides
2) subtract 27 from both sides

Answer 5

ok let me see if I can do it

Answer 6

5.4?
can you help me start it off

Answer 7

\(\large\color{slate}{ 5x−y=27 }\)
\(\large\color{slate}{ 5x−y\color{red}{+y}=27\color{red}{+y} }\)
\(\large\color{slate}{ 5x=27+y }\)
\(\large\color{slate}{ 5x\color{red}{-27}=27+y\color{red}{-27} }\)

so \(\large\color{slate}{ y= }\) ??

Answer 8

click on the question above or below, rejoin and question marks will dissapear

Answer 9

(apologize for the question marks)
can you see my reply, or should I repost it?

Answer 10

yes i can

Answer 11

okay, so then, tell me what you get for y (in the first equation, in terms of x)

Answer 12

ok one sec

Answer 13

take your time...

Answer 14

-22?

Answer 15

you already solve for y?

Answer 16

\(\large\color{slate}{ 5x\color{red}{-27}=27+y\color{red}{-27} }\)
\(\large\color{slate}{ 5x\color{red}{-27}=\color{red}{\cancel{27}}+y\color{red}{\cancel{-27}} }\)

Answer 17

and so you get that y=?

Answer 18

so basically 5-27?

Answer 19

was about to reply, and lost conection

Answer 20

\(\large\color{slate}{ y=5x-27 }\) is right

Answer 21

your second equation is: \(\large\color{slate}{ 2x+3y=-13 }\)

Substitute \(\large\color{slate}{ 5x-27 }\) instead of y, into the second equation.

Answer 22

\(\large\color{slate}{ 2x+3(5x-27)=-13 }\) like this

Answer 23

can you solve for x?

Answer 24

so were done with the first equation

Answer 25

yes (for now at least)

Answer 26

you need to solve for x.

Answer 27

ok

Answer 28

i kinda need help starting this one @SolomonZelman if you want to help

Answer 29

i will try one sec

Answer 30

2x + 3y = -3
x + 3y = -3
2x + y = y = -3
?

Answer 31

can you expand `3(5x-27)` ?

Answer 32

are you asking me can i do it or is that possible to expand it

Answer 33

can you do it

Answer 34

i'll try

Answer 35

3(5x-27)
3 + x = 27= 27 + 5x

Answer 36

Just like \(\large\color{slate}{ a(b-c)=a\cdot b - a\cdot c =ab-ac }\)

so is, \(\large\color{slate}{ 3(5x-27)=3\cdot 5x -3\cdot 27 =15x-81 }\)

Answer 37

so you get:
\(\large\color{slate}{ 2x+3(5x-27)=-13 }\)

\(\large\color{slate}{ 2x+15x-81=-13 }\)

Answer 38

now, add the x's on the left side, what do you get/

Answer 39

x = 1 right ?

Answer 40

@SolomonZelman

Answer 41

no that is not right-:(
Can you add the x's on the right side, and tell me what you get please.

Answer 42

I mean on the left side, excuse me

Answer 43

3x + 16x - 81 = -3 ?

Answer 44

15+2 = ?

Answer 45

17

Answer 46

@SolomonZelman