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Consider the geometric series
sin(2x) + sin(2x)cos(2x) + sin(2x)cos^2(2x)
for 0
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do you know the formuala for a geometric sum?
Is it Sn = a(1-r^n) /1-r ?
for an infinite series it is\[\sum_0^\infty ar^n=\frac a{1-r},~if~|r|<1\]
what is \(r\) in your case? is \(|r|<1\) ?
r would be cos2x .. i think ?
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yes, and is that <1 on the interval (0,pi/2) ?
-1<r<1 ?
that is the requirement to be able to use the formula I gave above is -1<cos(2x)<1 in the interval 0<x<pi/2 ?
yes!
awesome! then we can just plug into our formula for \(a\) and \(r\)
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ohhh okay! I think i understand it now :) Thank you :D !!
you're welcome :)
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