Question

find the difference (equation in comments) i forgot how to do this

Answer 1

\[\frac{ 2g }{ g ^{2}-g-6 }-\frac{ 1 }{ g-3 }\]

Answer 2

Hint: you can factor the denominator of the first term to:\[\frac{2g}{(g+2)(g-3)}\]

Answer 3

i got that but when it comes to getting common denominators on both and getting the numerator having it moved up there too i got lost because i didnt know what to do after that

Answer 4

\[\frac{2g}{g^2-g-6}-\frac{1}{g-3}=\frac{2g}{(g+2)(g-3)}-\frac{1}{g-3}\]\[=(\frac{1}{g-3})(\frac{2g}{g+2}-1)=[\frac{1}{g-3}][\frac{2g}{g+2}-1*(\frac{g+2}{g+2})]\]\[=[\frac{1}{g-3}][\frac{2g-(g+2)}{g+2}]\]\[=[\frac{1}{(g-3)(g+2)}][2g-(g+2)]\]