Question

A bowl contains 4 yellow marbles and 3 red marbles. Eric randomly draws 3 marbles from the bowl. He replaces each marble after it is drawn. What is the probability that he draws 1 yellow marble and 2 red marbles?

Answer 1

solve the equation 4/7 x 3/7 x 3/7 (x=multiply)

Answer 2

please you have to apply the definition of probability, namely
probability is equal to the ratio between favorable cases over possible cases, of course both favorable cases and possible cases are equally probable.

Answer 3

for example probability of getting 1 red marble is: 3/7
and probability of getting yellow marble is 4/7

Answer 4

now, keep in mind that probability of getting 1 yellow marble and 1 red marble and 1 red Marble is the product of the single probability, since after 1 draw the marble is replaced in the bowl

Answer 5

exactly so that was the correct equation

Answer 6

yes, I think so!

Answer 7

so out of these answers, would it be A?
A) 36/343
B) 108/343
C) 12/35
D) 4/35
@Michele_Laino @Jrigby20

Answer 8

yep

Answer 9

@kianatalani

Answer 10

we have to compute this:
\[\frac{ 4 }{ 7 }*\frac{ 3 }{ 7 }*\frac{ 3 }{ 7 }=...\]
please continue

Answer 11

i already did, a is correct

Answer 12

4*3*3=36

Answer 13

and 7*7*7=343

Answer 14

thus 36/343

Answer 15

@kianatalani @Michele_Laino hey kianatalani, which way was easier for you to understand?

Answer 16

your way :) thanks for the help! @Jrigby20

Answer 17

np kiantalani, glad i could help