8x^2+14x+5=0 completeing the squar
\(\large\color{slate}{ 8x^2+14x+5=0 }\) \(\large\color{slate}{ 8x^2+14x=-5 }\) \(\large\color{slate}{ 8(x^2+\frac{14}{8}x)=-5 }\)
Can you find the number that would make \(\large\color{blue}{ x^2+\frac{14}{8}x\color{red}{} }\) a perfect square trinomial once added?
the anwser is 1.25 and .5 but i am not sure how to get them
okay, can you answer the afore-posted question that I asked?
14/8 1.75.. but i dont no what x is
okay, lets first try to comprehend the concept of a perfect square trinomial. Do you know that: 1) \(\large\color{blue}{ x^2+4x+4 }\) 2) \(\large\color{blue}{ x^2-2x+1 }\) 3) \(\large\color{blue}{ x^2+6x+9 }\) 4) \(\large\color{blue}{ x^2+8x+16 }\) are perfect squares trinomials, and why this is so?
(say no, if you don't... and don't be afraid of anything...)
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