Question

rewrite the following equation in standard form
9-7x=(4x-3)^2+5

A) 16x^2-17x+5=0
B) 16X^2-17x-5=0
C) 16x^2-31x-5=0
D) 16x^2-31x+5=0

Answer 1

\[9-7x=(4x-3)^2+5\]?

Answer 2

you gotta multiply out on the right first
do you know how to do that?

Answer 3

no :( I honestly have no clue how to handle this one

Answer 4

@misty1212

Answer 5

first job it to square
\[9-7x=(4x-3)(4x-3)+5\]
\[9-7x=16x^2-24x+9+5\]
\[9-7x=16x^2-24x+14\]

Answer 6

then add \(7x\) to both sides and subtract \(9\) from both sides to get it equal to zero

Answer 7

you got it now?

Answer 8

im trying to figure it out right now

Answer 9

k

Answer 10

its 16x^2-17x+5=0 So B Right @misty1212

Answer 11

yes

Answer 12

oh not that is A

Answer 13

your answer was right but your choice was wrong
it is
\[16x^2-7x+5\] like you said, but the answer choice is A

Answer 14

lol I meant A thanks @misty1212

Answer 15

your welcome

Answer 16

i mean "you're welcome"