Question

Nicole is factoring 0.49t^18 - 25 by using the rule a^2 - b^2 = (a + b)(a - b). What will she use for the value of a?

A. 0.7t^9
B. 0.07t^9
C. 0.49
D. 0.7

I'd love some help with this please :)

Answer 1

lol thats somewat hard

Answer 2

i thought u were talking about factoring stuff like 4

Answer 3

but i think the answer is a

Answer 4

dont take my answer its a guess

Answer 5

Told you :)

Answer 6

Haha, it's alright :)

Answer 7

if \(0.49t^{18} = a^2\), and \(\large{a^b}^c=a^{b*c}\)
you can rewrite it as \(0.7^2*{a^9}^2\)

Answer 8

and so \(a=0.7a^9\)

Answer 9

I thought it was B

Answer 10

ugh
by a I meant t

Answer 11

\(0.49t^{18} = a^2\)
\(a=0.7t^9\)

Answer 12

wait emily those carrots mean "exponents"?

Answer 13

so my guess was correct @bibby ?

Answer 14

Wait. So that means the answer is C? Right

Answer 15

Yes Jack :) ^= exponents

Answer 16

ahhh

Answer 17

then i may be able to help

Answer 18

It's A. If you plug it in, I got that answer.

Answer 19

i think it is actulaly a

Answer 20

It's okay Jack! Bibby showed me the right thing. I confused what was where.

Answer 21

I got it now :)

Answer 22

no the answer would be a
0.49t^18 - 25 by using the rule a^2 - b^2 = (a + b)(a - b).

if we're treating \(0.49t^{18}\) as \(a^2\) and we want a, we can take the sqrt of both parts because \((ab)^m=a^mb^m\)

Answer 23

so the sqrt of 0.49 is 0.7 and \(\sqrt{t^{18}}={t^{18}}^\frac{1}{2}=t^{\frac{18}{2}}=t^9\)

Answer 24

so a is correct?

Answer 25

sorry my brain is loopy

Answer 26

can u show me how to do it @bibby

i want to learn ahead

Answer 27

Yeah I got that. A is correct. Thank you :)

Answer 28

Haha better then mine bibby