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Mathematics 16 Online
OpenStudy (anonymous):

Medal! HELP :D An equation is shown below: 2 over 3 multiplied by x plus 8 over 3 equals 2 to the power of x What is the solution to the equation? x = –2 x = –1 x = 1 x = 2

OpenStudy (anonymous):

OpenStudy (anonymous):

@haleyelizabeth2017

OpenStudy (haleyelizabeth2017):

Shoot, this is like what I am doing!

OpenStudy (anonymous):

lol @haleyelizabeth2017

OpenStudy (haleyelizabeth2017):

First, we need to multiply this whole thing by 3, to remove the fractions :)

OpenStudy (anonymous):

Alright, How would we do that

OpenStudy (haleyelizabeth2017):

Well just multiply it by 3 to get \(2x+8=6^x\)

OpenStudy (anonymous):

Haa i see

OpenStudy (haleyelizabeth2017):

The threes on the left in the denominators cancel :)

OpenStudy (anonymous):

@haleyelizabeth2017

OpenStudy (haleyelizabeth2017):

I'm still here :) my computer is just lagging :/ so it doesn't show me sometimes :(

OpenStudy (anonymous):

Yep that happens to me.. Keep disconnecting

OpenStudy (cwrw238):

there's a mistake in multiplying by 3 right hand side is 3 * 2^x not 6^x

OpenStudy (haleyelizabeth2017):

okay sorry lol I haven't done this in a while so I will let you finish :)

OpenStudy (cwrw238):

that's ok

OpenStudy (cwrw238):

2x + 8 = 3*2^x by inspection x = 2 as 2(2) + 8 = 3*2^2 12 = 12

OpenStudy (anonymous):

so 12 is the answer? @cwrw238

OpenStudy (anonymous):

Wait it cant be

OpenStudy (anonymous):

DAHH

OpenStudy (cwrw238):

n0 x = 2

OpenStudy (anonymous):

so D is right?

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

Thank You!

OpenStudy (cwrw238):

yw

OpenStudy (anonymous):

Can you help me with one more? @cwrw238

OpenStudy (cwrw238):

I cant think of an algebraic way to solve it one way would be graphical

OpenStudy (cwrw238):

ok

OpenStudy (anonymous):

Solve the following system of equations:

OpenStudy (anonymous):

3x - 2y = 6 6x - 4y = 14

OpenStudy (cwrw238):

you can solve these by the method of elimination

OpenStudy (anonymous):

0,0 6,14 Infinite solutions no solutions

OpenStudy (noelgreco):

I think the intent of the question is to simply substitute the possible responses into the equation.

OpenStudy (cwrw238):

first multiply the first equation by -2 then add it to the second

OpenStudy (anonymous):

Wait

OpenStudy (cwrw238):

yes - but its more instructive to try and solve them have you done solutions of systems of equations @AleshGames

OpenStudy (anonymous):

They are parallel

OpenStudy (anonymous):

does that mean the have no solutions?

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

There you go that is the answer.

OpenStudy (cwrw238):

right

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