Question

solve for the higher order derivative.

find "y" if y = x^3 - 3x.

please help me to solve this question.

Answer 1

"y" ?

Answer 2

does that mean second order derivative?

Answer 3

yes

Answer 4

yes sir

Answer 5

so you mean y''

Answer 6

first do you know how to find y'?

Answer 7

the power rule and constant multiple rule could come in handy here

Answer 8

i was wondering what "y" might mean lol

Answer 9

i dont knw how to find y

Answer 10

y is given

Answer 11

we are trying to find y'

Answer 12

you are doing derivative of x^3 and -3x

Answer 13

\[(x^n)'=nx^{n-1} \text{ is power rule }\]

Answer 14

i think combine terms

Answer 15

\[(cx)' =c(x)' \text{ by constant multiple rule } \\ =c(1) \text{ by the rule } \frac{dx}{dx}=1 \\ =c \text{ since 1 is multiplicative identity } \]

Answer 16

there are no like terms to combine

Answer 17

then?

Answer 18

have you ever seen the rules I have mentioned?

Answer 19

how can we solve that problem?

Answer 20

you need to know those rules to do this!!!

Answer 21

If you don't know these rules we can use the definition of derivative

Answer 22

but i need you to tell me if you do or do not know them

Answer 23

i do not know them

Answer 24

sorry

Answer 25

\[\frac{df(x)}{dx}=\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}\]
have you seen this definition before?

Answer 26

no

Answer 27

hmm... we are out out of luck then

Answer 28

because without knowing those rules and/or that definition there is no way I see how we can find the derivative

Answer 29

but i have a formula that ive know

Answer 30

oh what is it

Answer 31

y^1= x^3 - 3x

Answer 32

it will gonna be like this right?

Answer 33

that is the quotient rule

Answer 34

we don't have a quotient

Answer 35

how do you know about the quotient rule but not anything about the constant multiple rule, constant rule, or the power rule or even the definition of derivative?