Question

Velocity vs. Acceleration. what is the difference.

Answer 1

working on a math problem and dont know the difference really

Answer 2

think about a car
velocity is speed (except it can be negative)
acceleration is what happens when you push that big pedal on the right

Answer 3

namely it is the change in speed

Answer 4

The maximum height of a ball through straight up depends on the gravitational acceleration and the initial velocity. use dimensional analysis to determine the maximum height

Answer 5

max height is the vertex
what the monkey is "dimensional analysis"?

Answer 6

its like when you are crossing out all of the units to get to your final unit. its just a fancy word

Answer 7

for example
1minute 60 seconds
-------- x --------- = 60 seconds (cross out the minutes and it leaves seconds)
1 1 minute

Answer 8

so velocity/acceleration

Answer 9

The standard units for velocity is m/s,
and acceleration m^2/s

Answer 10

velocity is the first derivative of a function, acceleration is the instantaneous rate of change, or the second derivative.

Answer 11

m s 1
--- x ---- = ----
s m^2 m

i flipped it because at first i divided

Answer 12

Sorry, acceleration should've been m/s^2

Answer 13

i know that if you are give distance, take the derivative and get velocity, then take the derivative and get acceleration. i dont know how to relate them in the question

Answer 14

so final would be

seconds

Answer 15

??

Answer 16

can i take the anti-derivative of velocity to get the distance which would give me the maximum height

Answer 17

Wait, isn't acceleration m/s^2 not m^2/s

Answer 18

yes

Answer 19

I don't get how dimensional analysis would get you a maximum height...

Answer 20

There is this formula though:
s = ut + (at^2)/2
where s = distance travelled (maximum height?)
u = initial velocity
t = time taken
a = acceleration (-g)

Answer 21

Well, if you are doing something like \[
\frac LT\cdot \frac{T^2}L=T
\]Acceleration divided by velocity. This gives a time. If you want to make it meters again maybe you multiply by velocity again: \[
\left(\frac LT\right)^2\cdot \frac{T^2}{L} =L
\]

Answer 22

Just a thought

Answer 23

the final answer was
x^2
----
g

Answer 24

found a website with the same question
http://strohaber.webs.com/documents/QC1a-a.pdf

Answer 25

ok

Answer 26

I was saying \(v^2/a\).

Answer 27

why are they doing g^n and v^m

Answer 28

Because they are looking at the powers.

Answer 29

If the power is \(-1\) it means divide.

Answer 30

Aceleration is like moving. And Velocity is like the speed and momentum.