What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0?

a. 4x - y = 13
b. 4x + y = 13
c. 4x + y = -13

Question

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0?

a. 4x - y = 13
b. 4x + y = 13
c. 4x + y = -13

ajspeller · Answer

First you need to find the slope of 4x+y-2=0.

The slope of the line you have to create will have the same slope.
*parallel lines have the same slope

Ax+By=C
slope = -(A/B)

What is A in the given linear equation ?
What is B in the given linear equation ?

daniellelovee · Answer

Wouldn't it be easier to solve if he/she just substituted and then worked PEMDAS backwards? @ajspeller

ajspeller · Answer

You could but if the answer is the last option in the multiple choice then worked out the problem 3 times instead of just once.  But yes, you are correct that is an option.

daniellelovee · Answer

oh well I would do that just because one could always go back and check and it'll be easier

anonymous · Answer

I dont get it =/

ajspeller · Answer

I recommend knowing how to come to the answer because as some point the questions will not be multiple choice.

4x+y=2

Ax+By=2

Slope = -(A/B) = -(4/1)=-4

Then use the point slope formula.

(y-y_1)=m(x-x_1)

(x_1,y_1) -> (4,-3)

(y-(-3))=-4(x-4)
(y+3)=-4x+16
y=-4x+13

4x+y=13 --> Solution