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Mathematics 9 Online
OpenStudy (clamin):

PLEASE HELP!! MEDAL!! The height of Carl, the human cannonball, is given by h(t)=-16t^2+56t+40 where h is in feet and t is in seconds after the launch. a.) What was his height at the launch? b.) What is his maximum height? c.) How long before he lands in the safety net, 8 feet above the ground?

OpenStudy (whpalmer4):

No, the previous poster's advice will lead you astray. For a), you simply use the formula for \(h(t)\) at \(t = 0\): calculate \(h(0)\) for the initial height at the time of the launch. b and c) can be solved as suggested. Note that for c) you'll have two solutions for the value of \(t\) which makes \(h(t) = 8\), but only one of them will make sense in the context of this problem.

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