What is the value of A. 512 B. 64 C. 16 D. 8
you have to find out cube root here. what are you not getting? how to split it?
Hint.. check out the last digit of the numbers after raising their power to 3.. for instance.. 2^3 = 2 * 2 * 2 = 8.. Answer`s last digit will match with last digit of given problem..
Like 8^3 .. (8 is selected from given options) 8 * 8 * 8 = x4 * 8 = xx2 where, 2 is the last digit.. and in given problem last digit is 6.. so 8 is not the answer..
ok but what im not getting is where do you get the 8*8*8 from like what would be the number for my question?
so to start with basic u may split it as 2*something then again and with practice u will get hang of it slowly...
started with 2 as its an even number.... or u may start with 4 also as 4*4=16 and last digit here is 6..... so u may go with prime factorisation method... u know this method?
select from options... 8 , 16, 64 and 512
suppose its 64=2*2*2*2*2*2 ... now u see 2 appears 6 times... so while taking cube root we get 2 .. 2 times... means its 4...
Here as options are given u can go ahead with options also.... starting from least one to make task easier..
a simpler way to add on vedic`s point.. 64 ^3 = 64 * 64 * 64 multiply last digit of 1st two terms.. 64 * 64 = xx6 ..( as 4 * 4 = 16) now continue.. xx6 * 64 = xxx4 ... ( as 6 * 4 = 24).. again last digit..
so 512
how u arrived at 512?
it was just a rough estimate
your rough estimate was totally wrong.... just think if u multiply 512 three time would u get a four digit number???
ohhhhhh so its between 64 and 16
yup.... but now see 4*4*4=64... so last digit would be 4 if we cube 64.... so now we r left with 16.... as 6*6*6= 216.. so last digit 6... so 16 ..
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