Running out of time What is the slope-intercept form of the function that contains the point (3, 4) and has a slope of 2? y = x +
y=mx+b so you need to find b so this is that you do (3,4)- 4 goes in for y and 3 goes in for x like this 4=3+b then subtract 3 from 4 and you get 1 and the slope is 2 so y=2x+1
y=mx+b 4=2(3)+b 4= 6+b 4-6=b -2=b y=2x-2
Dont you mean + 2?
Point (3,4) slope = 2 point-slope form y - y1 = m(x-x1) y - 4 = 2*(x-3)
put that into form they want, y=mx + b, by distributing the 2, and isolating Y by itself
y=2x+1 is what i had
so im right?
y - 4 = 2*(x-3) y - 4 = 2x - 6 y = 2x - 6 + 4 y = 2x - 2
uh it wont let me put a - tho, it has a + and i cant change it
+ (-2)
plus a negative, is the same as, minus
y = 2x + (-2)
Ok i guess... im pretty unsure :/
that is what it is, type -2 for the b spot in y=mx+b
m=2 b = -2
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