Question

i need help finding the vertex and roots of
y=(x+3)(x-3) y=-x^2+6

y=x^2+9 x+20

Answer 1

@Mimi_x3

Answer 2

@TheSmartOne

Answer 3

@iambatman

Answer 4

hi

Answer 5

HI

Answer 6

could you help me
?

Answer 7

sure dear
is this three different questions?

Answer 8

yes

Answer 9

\[y=(x+3)(x-3) \\
y=x^2-9\] vertex is \((0,-9)\)

Answer 10

how do i do that?

Answer 11

since \(x^2\) is positive of zero then \(x^2-9\geq -9\) so the vertex is \((0,-9)\)

Answer 12

how do you do what ?

Answer 13

one sec

Answer 14

how do i get negitive 9

Answer 15

*negative

Answer 16

my multiplying \\[(x+3)(x-3)\]

Answer 17

Oh. ( I Had no idea[this is not sarcastic i really didn't know])

Answer 18

G.T.G.