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Mathematics 13 Online
OpenStudy (anonymous):

How do you solve quadratic equations in one variable?

OpenStudy (anonymous):

How can you derive the quadratic formula? How can you solve quadratic equations based on the initial form of the equation?

OpenStudy (campbell_st):

the quadratic formula can be derived from completing the square... and if the quadratic is in the form \[ax^2 + bx + c = 0\] then the formula is \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

OpenStudy (anonymous):

Thank you. Can you help with the other two, I'm just having trouble understanding these three problems

OpenStudy (anonymous):

I'll give medals and fan

OpenStudy (anonymous):

Can you help with the rest @campbell_st?

OpenStudy (campbell_st):

what is the rest..?

OpenStudy (anonymous):

The very last question, I found the answer for the first

OpenStudy (campbell_st):

my 1st post cover's it... if you know the coefficients a, b and c then just substitute and calculate e.g. \[2x^2 + 10x + 3 = 0\] a = 2, b = 10 and c = 3 so \[x = \frac{-10 \pm \sqrt{10^2 - 4 \times 2 \times 3}}{2 \times 2} = \frac{-10\pm \sqrt{76}}{4}\] and then simplify further there are 2 answers \[x = \frac{-10 + \sqrt{76}}{4}~~~ and ~~~ x = \frac{-10 - \sqrt{76}}{4}\]

OpenStudy (anonymous):

This cover's all three questions?

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