How do you solve quadratic equations in one variable?
How can you derive the quadratic formula? How can you solve quadratic equations based on the initial form of the equation?
the quadratic formula can be derived from completing the square... and if the quadratic is in the form \[ax^2 + bx + c = 0\] then the formula is \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Thank you. Can you help with the other two, I'm just having trouble understanding these three problems
I'll give medals and fan
Can you help with the rest @campbell_st?
what is the rest..?
The very last question, I found the answer for the first
my 1st post cover's it... if you know the coefficients a, b and c then just substitute and calculate e.g. \[2x^2 + 10x + 3 = 0\] a = 2, b = 10 and c = 3 so \[x = \frac{-10 \pm \sqrt{10^2 - 4 \times 2 \times 3}}{2 \times 2} = \frac{-10\pm \sqrt{76}}{4}\] and then simplify further there are 2 answers \[x = \frac{-10 + \sqrt{76}}{4}~~~ and ~~~ x = \frac{-10 - \sqrt{76}}{4}\]
This cover's all three questions?
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