Using the quadratic formula, Solve this equation h^2-2h=8 .. So x = ?
\(\large\color{slate}{ h^2-2h=8 }\) add 1 to both sides, \(\large\color{slate}{ h^2-2h\color{red}{+1}=8\color{red}{+1} }\) you get: \(\large\color{slate}{ h^2-2h+1=8+1 }\) NOW, complete the square.
(And you know what 8+1 is)
9 !
HI!!
Dont you need to square root, 3 is not the right answer.. so confused
if you really want to use the quadratic formula, rather than completing the square (which would be easier in this case) then the first thing you need to do is write \[h^2-2h-8=0\] then use \[h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1,b=-2,c=-8\]
you can factor it
it would be easier to complete the square, still easier to factor \[h^2-2h-8=(h+2)(h-4)\]
completing the square was the first that came on my mind.
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