y = -x + 3 y = x - 3 A. (0, 3) B. (-3, 0) C. (3, 0) D. (0, -3) im a bit confused with it being a negative. can someone just walk me through with A and then with the negatives so i get it?
What are your directions? Is it elimination?
What is the solution to the system of equations graphed below? it basically has the lines and the equation thingy.. But that's all of it.. @JuanitaM
You can find solution either via elimination or substitution. In this case eliminate.
you can eliminate A
You have the equations for two lines. See how both are equal to y? That means you can set them equal to each other: \[y = -x + 3 = x - 3\] We can then solve for x: \[-x + 3 = x-3\] Move the x terms to one side and the numbers to the other side: \[2x = 6\] Now solve for x. Once you have x, plug into either of these equations to solve for y: \[y = -x + 3 = x - 3\]
(3,0)
Yep!
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