if x, y, and z are positive numbers and 2x=3y=4z, then the value of x+y+z is how many times the value of x? and why?

Question

greencat · Answer

$$x=z$$
$$z=\frac{1x}{2}$$
$$y=\frac{2x}{3}$$

greencat · Answer

$$x+y+z=x+\frac{ 1x }{ 2 }+\frac{ 2x }{ 3 }$$

anonymous · Answer

thank you so much =)

greencat · Answer

Don't forget to add the fractions.

greencat · Answer

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greencat · Answer

Do you need help getting the final answer?

anonymous · Answer

is it 13/6?

greencat · Answer

Don't forget x. :)

$$\frac{13x}{6}$$

anonymous · Answer

thank you so much =)

jim_thompson5910 · Answer

Another way to get the same answer

W = x+y+z
W = 12(x+y+z)/12
W = (12x+12y+12z)/12
W = (6*2x+4*3y+3*4z)/12
W = (6*2x+4*2x+3*2x)/12
W = (12x+8x+6x)/12
W = (26x)/12
W = (13/6)*x

anonymous · Answer

that is really helpful as well thank you =)

anonymous · Answer

Where did you get the 12 from?

kamibug · Answer

$\huge\cal\color{green}{Welcome~to~Openstudy!~:)}$